HomeUnit Conversion › Joules to Foot-pounds

Joules to Foot-pounds (J to ft·lbf)

Convert joules to foot-pounds: 1 J = 0.737562 ft·lbf. Exact conversion factor, formula, 22-row table and worked examples, with JSON API and MCP access.

Formula

1 J = 0.737562 ft·lbf

foot-pounds = joules × 0.7375621493 — reverse: joules = foot-pounds × 1.355817948

The factor is derived from the SI definitions of both units (base unit: J) as listed in NIST SP 811; results on this page are shown to 6 significant figures, the API returns up to 12.

Worked examples

Joules to foot-pounds conversion table

Joules (J)Foot-pounds (ft·lbf)
10.737562
21.47512
32.21269
42.95025
53.68781
64.42537
75.16294
85.9005
96.63806
107.37562
1511.0634
2014.7512
2518.4391
3022.1269
4029.5025
5036.8781
7555.3172
10073.7562
200147.512
250184.391
500368.781
1000737.562

FAQ

How many foot-pounds are in one joule?

1 J = 0.737562 ft·lbf. The factor comes from the SI definitions of both units (NIST SP 811 / BIPM), so it is exact or correct to at least 10 significant figures.

What is the formula to convert joules to foot-pounds?

Multiply the value in joules by 0.7375621493: foot-pounds = joules × 0.7375621493. For example, 5 J = 3.68781 ft·lbf.

How do I convert foot-pounds back to joules?

Multiply by the inverse factor 1.355817948 (joules = foot-pounds × 1.355817948), or use the foot-pounds-to-joules page.

Related conversions

Machine access

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